Jenny,
I may be missing something, but I think the way to find a per-thousand
figure is simply:
( (freq of word) / (no of words in text) ) * 1000
eg (200/4000) * 1000 = 50
or (2646/55166) * 1000 = 48 (to nearest whole number)
- of course it's up to you whether to round to nearest whole n7umber,
or give the answer to 2 decimal palces (47.96) or some other level
of accuracy; but since generally a text is only a sample or
approximation of the language you are studying, it is sensible not to
claim too much accuracy/significance.
eric atwell
On Mon, 12 Sep 2005, Jenny Eagleton wrote:
> Hello Corpora and Statistics Experts,
>
> This is a very simple question for all the
> corpora/statistics experts
> out there, but this novice is not really
> mathematically inclined. I
> understand Biber's principle of "normalization,
> however I am not sure
> about how to calculate it. I want frequency counts
> normalized per
> 1,000 words of text. I can see how to do it if the
> figures are even,
> i.e. if I have a corpus of 4,000 words and a
> frequency of 200, 
> I would have a normalized figure of 50.
>
> But for mixed numbers, how would I calculate the
> following: For
> example if I have 2,646 instances of a certain
> kind of noun in a
> corpus of 55,166 how would I calculate the
> normalized figure per
> 1,000 words?
>
> Regards,
>
> Jenny
> Research Assistant
> Dept. of English & Communication
> City University of Hong Kong
>
>
>
-- Eric Atwell, Senior Lecturer, Language research group, School of Computing, Faculty of Engineering, University of Leeds, LEEDS LS2 9JT, England TEL: +44-113-2335430 FAX: +44-113-2335468 http://www.comp.leeds.ac.uk/eric
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